Categories
Algrebra Math

Problem from mathematical quickies – #94 – “Simultaneous Equations”

The problem is to solve an equation of 5 variables with 5 equations. Making it into a matrix the left side looks like an identity matrix. The first time I solved this I did it long hand – which took forever – then I took another look and saw what they person framing the problem was thinking. Which is cool since this trick should make it easier to attack matrix reduction for some annoying cases. 

Solve the system of simultaneous equations
Solve the system of simultaneous equations

Sum all of the rows to create the new vector S. Then since all the columns of S have the same value it can be normalized so all the values of S are unity. Then by subtracting S from each of the rows (a..e) we create a new matrix M. Multiply M by negative 1 to keep the values at unit as opposed to negative unity and the solution is done. Most important it is done without the page of long hand reduction. 

simultaneous_equation_mathematical_quickies_numb94_answer 

Categories
Algrebra Math

Problem from mathematical quickies – #136 – “A Consistent Sum”

 

Solve for K
Solve for K
Categories
Uncategorized

Training May 30th.

I got like 12 minutes of open mat time.

10 Ikyo-undo

10 Nikyo-undo

10 Sankyo-undo

10 Kote-Gaeshi-undo

20 Tekubi-kosa-undo, Tekubi-joho-kosa-undo -> Still not getting these right. Weight not staying under side.

Categories
Calculus Math

Area of a right triangle

Ok, one of the first equations learned in school is that the area of a right triangle is half the base times the height. Obvious since the base times height gives the area of a rectangle and that is twice the are of the triangle in question. Using calculus though you can say the same thing as:

Area of a right triangle via integration
Area of a right triangle via integration
Categories
Geometry Math

Prove the Pythagorean theorem

The pythagorean theorem states that for a right triangle the sum of the squares of the opposite and adjacent sides is equal to the square of the hypotenuse. I used a graphical proof to prove this theorem.

Graphical proof for the pythagorean theorem
Graphical proof for the pythagorean theorem
Categories
Math

Human skills are apparently perishable

I realized that there are things that are important to me other then just martial arts that require constant training if I do not want to loose skills I worked so hard to acquire.  One of those things was the ability to describe aspects of the world around me mathematically. I keep reaching back for things I know I once could do with little effort and finding they were either much harder than I remembered – or worse yet now beyond my ability. 

 So – I am going to try re-working through the basics and working up my skill level again. Hopefully to where I can get better then I once was.